H(t)=16t^2+48t+100

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Solution for H(t)=16t^2+48t+100 equation: 



(H)=16H^2+48H+100

We move all terms to the left:

(H)-(16H^2+48H+100)=0

We get rid of parentheses

-16H^2+H-48H-100=0

We add all the numbers together, and all the variables

-16H^2-47H-100=0

a = -16; b = -47; c = -100;
Δ = b2-4ac
Δ = -472-4·(-16)·(-100)
Δ = -4191
Delta is less than zero, so there is no solution for the equation

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